JAVA LAB

-

CLICK HERE:- JAVA LAB 

Comments

Post a Comment

Popular posts from this blog

Design GUI to handle Choice Control event.

-
  /* Write an applete code to demonstrate usgae of choice control */ import java.awt.*; import java.awt.event.*; import java.applet.*; /* <applet code="ChoiceDemo" width=300 height=100> </applet> */       public class ChoiceDemo extends Applet implements ItemListener {     Choice c1,c2;     public void init()     {     c1 = new Choice();     c2 = new Choice();         // add items to first choce controls     c1.add( "Windows XP" );     c1.add( "Windows 8" );     c1.add( "Windows 10" );     c1.add( "Ubuntu" );     // add items to second choce controls     c2.add( "Google Chrome" );     c2.add( "Mozila Firefox" );     c2.add( "Opera" );     // adding choice controls to applet window     add(c1);     add(c2);     //regisre with event listeners     c...
Read more

Write a Java program that reads an integer number (between 1 and 255) from the user and prints the binary representation of the number. The answer should be printed as a String. Note: The output displayed should contain 8 digits and should be padded with leading 0s(zeros), in case the returned String contains less than 8 characters. For example, if the user enters the value 16, then the output should be 00010000 and if the user enters the value 100, the output should be 01100100 (Hint : You may use String.format() method for the expected output)

-
 /* Binary Representation of given number */ import java.util.*; class Decimal_Binary_1B { public static void main(String args[]) { Scanner s = new Scanner(System.in); System.out.println("Enter an integer between 1 to 255"); int n=s.nextInt(); if(n<1 || n>255) { System.out.println("Input must enter in between 1 to 255"); } else { String b=String.format("%08d",Integer.valueOf(Integer.toString(n,2))); //Integer.BinaryString(n) System.out.println("Binary value is:"+b); } } }
Read more